![SOLVED: f(x)=∑n=1^∞ bnsin((n π x)/(L)) satisfies: f^'(x)=∑n=1^∞(n π)/(L) bncos((n π x)/(L))+∑n=1^∞(2)/(L)((-1)^n f(L)-f(0)) cos((n π x)/(L))+(1)/(L)( f(L)-f(0)) 2 10 3. Consider the function f(x)=e^(p-q) x on the interval [0, r-q]. (a) Find the ...](https://cdn.numerade.com/ask_images/14702e7a6c094fe3ad8e8294ad4aab7e.png "SOLVED: f(x)=∑n=1^∞ bnsin((n π x)/(L)) satisfies: f^'(x)=∑n=1^∞(n π)/(L) bncos((n π x)/(L))+∑n=1^∞(2)/(L)((-1)^n f(L)-f(0)) cos((n π x)/(L))+(1)/(L)( f(L)-f(0)) 2 10 3. Consider the function f(x)=e^(p-q) x on the interval [0, r-q]. (a) Find the ...")
SOLVED: f(x)=∑n=1^∞ bnsin((n π x)/(L)) satisfies: f^'(x)=∑n=1^∞(n π)/(L) bncos((n π x)/(L))+∑n=1^∞(2)/(L)((-1)^n f(L)-f(0)) cos((n π x)/(L))+(1)/(L)( f(L)-f(0)) 2 10 3. Consider the function f(x)=e^(p-q) x on the interval [0, r-q]. (a) Find the ...
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![A resistance of \\[300\\Omega \\] and an inductance of \\[\\dfrac{1}{\\pi }\\] henry are connected in series to an A.C. voltage of \\[20 volts\\] and \\[200Hz\\] frequency. The phase angle between the voltage](https://www.vedantu.com/question-sets/bd53b45d-7857-4c65-9934-0c4a650cab894152570357455305689.png "A resistance of \\[300\\Omega \\] and an inductance of \\[\\dfrac{1}{\\pi }\\] henry are connected in series to an A.C. voltage of \\[20 volts\\] and \\[200Hz\\] frequency. The phase angle between the voltage")
A resistance of \\[300\\Omega \\] and an inductance of \\[\\dfrac{1}{\\pi }\\] henry are connected in series to an A.C. voltage of \\[20 volts\\] and \\[200Hz\\] frequency. The phase angle between the voltage
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